3/4x^2+7x+16=0

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Solution for 3/4x^2+7x+16=0 equation: 


x in (-oo:+oo)

(3/4)*x^2+7*x+16 = 0

3/4*x^2+7*x+16 = 0

DELTA = 7^2-(3/4*4*16)

DELTA = 1

DELTA > 0

x = (1^(1/2)-7)/(3/4*2) or x = (-1^(1/2)-7)/(3/4*2)

x = -4 or x = -16/3

x in { -16/3, -4 }

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